16 exam-style question sets on Measurement (Paper 2), each with a hint and a fully worked answer. The app holds 80 questions on this section in total, including variants of every set below, and lets you mark yourself part by part.
Practise this section in the app →
Question 1
The tutor of a Saturday school wrote the explanations in TABLE 1 on the board before a lesson on measurement and plans.
TABLE 1: EXPLANATIONS ON THE BOARD
| LETTER | EXPLANATION |
|---|---|
| A | The system of measurement that works with feet, miles, ounces and pints |
| B | How much a container is able to hold when it is full |
| C | How far you walk if you go once right around the boundary of a flat shape |
| D | A drawing that shows what the front, back or side of a building looks like from the outside |
| E | The system of measurement that works with metres, grams and litres |
| F | How much surface a flat shape covers, measured in square units |
| G | A drawing that shows the rooms of a building as seen from directly above |
| H | How much space a solid object takes up, measured in cubic units |
Which explanation in TABLE 1 belongs to EACH of the concepts below? Answer with the letter (A–H) of the explanation only, for example (e) I.
- aVolume (2)
- bFloor plan (2)
- cMetric system (2)
- dPerimeter (2)
Hint
Capacity is about what a container can HOLD; volume is about the space an object TAKES UP.
Worked answer
a) H ✓✓A — volume is the space that an object takes up; B describes capacity.
b) G ✓✓A — a floor plan is a view from above; D describes an elevation.
c) E ✓✓A — metres, grams and litres are metric units.
d) C ✓✓A — perimeter is the distance around a shape.
Modelled on Nov 2024 Paper 2, Question 1.1 — same skills, new scenario.
Question 2
A landscaper uses square concrete slabs to pave a courtyard. The diagram shows the top view of ONE slab.
DIMENSIONS OF A SLAB: length = 450 mm, width = 450 mm, thickness = 50 mm
- aWrite 450 mm in metres. (2)
- bWhich ONE of the formulae below gives the volume of a slab? - A Volume = 2 × (length + width) - B Volume = length × width × thickness - C Volume = length + width + thickness (2)
- cThe slabs are laid edge to edge in ONE straight row. How many slabs are needed for a row that is 8 100 mm long? (3)
This question has a diagram, shown in the app.
Hint
There are 1 000 mm in a metre, and volume always multiplies THREE dimensions.
Worked answer
a) 450 mm ÷ 1 000 ✓C = 0,45 m ✓A
b) B ✓✓A — a volume is the product of three lengths; A is the formula for a perimeter.
c) Number of slabs = 8 100 mm ÷ 450 mm ✓M ✓A = 18 slabs ✓CA
Modelled on Nov 2024 Paper 2, Question 1.2 — same skills, new scenario.
Question 3
A school library packs books into plastic crates when the library is painted. The sketch shows ONE crate with its inside dimensions. A rubber edging strip is glued around the top rim of each crate so that it does not cut the learners' hands.
You may use the following formula:
Perimeter of a rectangle = 2 × (length + width)
- aThe van with the crates left the school at 07:45 and arrived at the storeroom at 10:20. Determine how long the trip took. (2)
- bBooks that are 2,4 cm thick are packed flat, one on top of the other. Calculate the difference between the height of a stack of 14 books and the height of the crate. (4)
- cThe shop sells the rubber strip by the full metre only. Calculate the length of strip that must be bought for the top rims of FIVE crates. (5)
This question has a diagram, shown in the app.
Hint
The top rim of the crate has the same perimeter as its base. Convert to metres before you decide how many full metres to buy.
Worked answer
a) From 07:45 to 10:20 ✓M = 2 h 35 min ✓A
b) Height of the stack = 14 × 2,4 cm ✓M = 33,6 cm ✓A
Difference = 36 cm − 33,6 cm ✓M = 2,4 cm ✓CA
(The stack is 2,4 cm LOWER than the 36 cm height.)
c) Perimeter = 2 × (58 cm + 38 cm) ✓SF
= 192 cm ✓A
For 5 crates: 192 cm × 5 = 960 cm ✓M
= 9,6 m ✓C
Buy 10 m ✓R (it is sold only in full metres, so round UP)
Modelled on Nov 2024 Paper 2, Question 3.1 — same skills, new scenario.
Question 4
A screen-printing business makes round fabric badges for a youth camp. Each badge has a diameter of 6 cm and a small buttonhole with an area of 0,2 cm². ONE side of every badge is coated with fabric ink. The ink has a spread rate of 8 m² per litre and is sold in 500 mℓ tubs.
You may use the following formulae (use π = 3,142):
Circumference of a circle = π × diameter
Area of a circle = π × radius²
- aA border is stitched right around the edge of every badge. Calculate the length of the border of ONE badge. (2)
- bWrite down the radius of a badge. (2)
- cThe owner states that ONE 500 mℓ tub of ink is enough to coat one side of 1 200 badges. Verify, showing ALL calculations, whether this statement is valid. NOTE: 1 m² = 10 000 cm² (9)
This question has a diagram, shown in the app.
Hint
Subtract the buttonhole from ONE badge first; convert the total area to m² before you use the spread rate.
Worked answer
a) Circumference = 3,142 × 6 cm ✓SF
= 18,852 cm ✓A
b) Radius = 6 cm ÷ 2 ✓M = 3 cm ✓A
c) Area of a circle = 3,142 × (3 cm)² ✓SF
= 28,278 cm² ✓A
Area to be coated on one badge = 28,278 cm² − 0,2 cm² ✓M = 28,078 cm² ✓CA
Area of 1 200 badges = 28,078 cm² × 1 200 ✓M = 33 693,6 cm²
= 33 693,6 cm² ÷ 10 000 ✓C = 3,3694 m²
Ink needed = 3,3694 m² ÷ 8 m²/ℓ ✓M = 0,4212 ℓ
= 0,4212 ℓ × 1 000 ✓C = 421,17 mℓ
421,17 mℓ is less than 500 mℓ, so the statement is VALID ✓O
Modelled on Nov 2024 Paper 2, Question 3.2 — same skills, new scenario.
Question 5
A hardware shop sells an assorted pack of fasteners in a cube-shaped plastic tub, as shown in the sketch.
The volume of the tub is 1 728 cm³.
You may use the following formula:
Volume of a cube = side × side × side
NUMBER OF ITEMS PER TYPE OF FASTENER
| TYPE OF FASTENER | NUMBER OF ITEMS |
|---|---|
| Wood screws | 12 |
| Machine screws | 9 |
| Wall plugs | 6 |
| Washers | 8 |
| Cup hooks | 5 |
| TOTAL | 40 |
- aCalculate the length of ONE side of the tub in millimetres. (4)
- bOne item is taken from the tub without looking. Determine, as a decimal, the probability that it is a wood screw or a machine screw. (3)
This question has a diagram, shown in the app.
Hint
The side of a cube is the number that, multiplied by itself three times, gives the volume: use the ∛ key, or test whole numbers.
Worked answer
a) side × side × side = 1 728 cm³
side = ∛1 728 ✓M
= 12 cm ✓A
= 12 cm × 10 ✓C = 120 mm ✓CA
(Check: 12 × 12 × 12 = 1 728)
b) P(wood screws or machine screws) = ✓M ✓M
= = 0,525 ✓A
Modelled on Nov 2024 Paper 2, Question 3.3 — same skills, new scenario.
Question 6
A candle-making workshop melts different kinds of wax in a closed cylindrical melting pot with a diameter of 0,6 m and a height of 0,9 m. To save electricity, the outside of the pot is wrapped in an insulating jacket. The tap, the lid handle and the thermometer take up 4% of the outside surface, and this part is NOT covered.
MELTING POINTS OF THE WAXES THAT THE WORKSHOP USES
| TYPE OF WAX | MELTING POINT (°C) |
|---|---|
| Soy wax | 49 |
| Beeswax | 63 |
| Coconut wax | 38 |
| Gel wax | 82 |
| Paraffin wax | 58 |
| Palm wax | 60 |
You may use the following formulae (use π = 3,142):
°C = (°F − 32) ÷ 1,8
Area of the curved surface of a cylinder = π × diameter × height
The total area of the TWO circular ends of the pot is 0,57 m².
- aA mixture of all six waxes is heated slowly from room temperature. Which wax will be the FOURTH one to melt? (2)
- bWrite down the type of wax that melts at 58 °C. (2)
- cAn American supplier asks at what temperature beeswax melts. Give the melting point of beeswax in degrees Fahrenheit (°F). (4)
- dCalculate, rounded to TWO decimal places, the area (in m²) of the pot that is covered by the insulating jacket. (7)
This question has a diagram, shown in the app.
Hint
The jacket covers the curved surface AND the two ends, except for 4% of the total — so work out 96% of the total outside area.
Worked answer
a) Palm wax ✓✓A (from the lowest temperature: 38 °C → 49 °C → 58 °C → 60 °C, so the fourth wax to melt is palm wax)
b) Paraffin wax ✓✓RT
c) 63 = (°F − 32) ÷ 1,8 ✓SF
°F − 32 = 63 × 1,8 ✓M = 113,4
°F = 113,4 + 32 ✓M
= 145,4 °F ✓A
d) Curved surface = 3,142 × 0,6 m × 0,9 m ✓SF
= 1,6967 m² ✓A
Total outside surface = 1,6967 m² + 0,57 m² ✓M
= 2,2667 m² ✓CA
Percentage that is covered = 100% − 4% = 96% ✓M
Area to be covered = 96% × 2,2667 m² ✓M
= 2,18 m² ✓CA
Modelled on Nov 2024 Paper 2, Question 4.1 — same skills, new scenario.
Question 7
The Naidoo family wants to pave their rectangular driveway, which is 12 m long and 3,5 m wide, with concrete pavers.
- The paving pattern uses 50 pavers per square metre.
- 5% more pavers must be ordered, because pavers at the edges are cut and the off-cuts are thrown away.
- The pavers are sold only in full pallets of 400 pavers at R1 980,00 per pallet.
- Bedding sand and edging cost R3 450,00 in total.
- The paving team charges R165,00 per square metre for labour.
- aDetermine the number of pallets of pavers that the family must order. (5)
- bMr Naidoo budgeted R22 000,00 for the whole project (pavers, sand and edging, and labour). Verify, showing ALL calculations, whether his budget is enough. (7)
- cThe family wants to save money and asks the supplier to open a pallet and sell them only the pavers that they need. Give ONE reason why a supplier would refuse. (2)
This question has a diagram, shown in the app.
Hint
Work out the AREA first; the number of pavers, the 5% and the pallets all follow from it.
Worked answer
a) Area = 12 m × 3,5 m ✓M = 42 m² ✓A
Pavers = 42 × 50 ✓M = 2 100
With 5% extra: 2 100 × 1,05 ✓M = 2 205
Number of pallets = 2 205 ÷ 400 = 5,513
≈ 6 pallets ✓R (only full pallets are sold, so round UP)
b) Pallets: 6 × R1 980,00 ✓M = R11 880,00 ✓A
Labour = R165,00 × 42 m² ✓M = R6 930,00 ✓A
Total = R11 880,00 + R3 450,00 + R6 930,00 ✓M
= R22 260,00 ✓CA
R22 260,00 is MORE than the budget of R22 000,00, so the budget is NOT enough ✓O
c) Loose pavers from an opened pallet are difficult to sell, to store and to deliver, so the supplier would be left with stock that nobody wants ✓✓O (or: counting out loose pavers costs the supplier time and labour).
Modelled on Nov 2024 Paper 2, Question 4.2 — same skills, new scenario.
Question 8
An energy company compares the hub heights of three models of wind turbine for a new wind farm. The heights are shown in the bar graph. The brochure of Model B also gives its hub height in feet (ft).
- aThe hub height of Model B is given in metres AND in feet. Use these two values to work out how many metres there are in ONE foot. Round your answer to THREE decimal places. (3)
- bWrite the ratio of the hub heights Model A : Model B : Model C in simplified form. (4)
This question has a diagram, shown in the app.
Hint
A conversion factor tells you how many metres make ONE foot — divide the metres by the feet.
Worked answer
a) 394 ft = 120 m ✓RD
1 ft = 120 ÷ 394 ✓M
= 0,30457… ≈ 0,305 m ✓R
b) 80 : 120 : 140 ✓RD
Divide every term by 20 ✓M
= 4 : 6 : 7 ✓A ✓CA (fully simplified)
Modelled on Nov 2024 Paper 2, Question 5.2 — same skills, new scenario.
Question 9
The table below shows the areas of the seven wards of a rural municipality. The area of each ward is divided into farmland and conservation land. The percentage for Ward 7 (a small harbour island) was left out.
AREA AND POPULATION OF THE WARDS
| WARD | FARMLAND (km²) | CONSERVATION LAND (km²) | TOTAL AREA (km²) | % OF THE TOTAL AREA | POPULATION |
|---|---|---|---|---|---|
| Ward 1 | 425,0 | 113,0 | 538,0 | 26,9 | 84 310 |
| Ward 2 | 312,0 | 86,0 | 398,0 | 19,9 | 61 450 |
| Ward 3 | 248,0 | 154,0 | 402,0 | 20,1 | 39 870 |
| Ward 4 | 189,0 | 32,0 | 221,0 | 11,1 | 52 260 |
| Ward 5 | 276,0 | 41,0 | 317,0 | 15,9 | 47 125 |
| Ward 6 | 98,0 | 25,2 | 123,2 | 6,2 | 28 640 |
| Ward 7 | 0,6 | 0,2 | 0,8 | 310 | |
| TOTAL | 2 000,0 |
- aA point on the map of the municipality is chosen at random. Determine, as a decimal, the probability that the point lies in Ward 3. (2)
- bShow, with calculations, that the total area of Ward 4 is approximately half of the farmland of Ward 1. (3)
- cCalculate the population density (number of people per km²) of Ward 2, rounded to the nearest whole number. Population density = population ÷ total area (3)
- dGive a reason, supported by calculations, why the percentage for Ward 7 was left out of the table. (4)
Hint
A percentage of the total area tells you how likely a random point is to land there.
Worked answer
a) P = 20,1% ✓RT = 0,201 ✓A (the percentage of the total area IS the probability)
b) 221,0 km² ÷ 425,0 km² ✓RT ✓M
= 0,52, which is close to a half (0,5) ✓O
c) Population = 61 450 and area = 398,0 km² ✓RT
Density = 61 450 ÷ 398,0 ✓M
= 154,4 ≈ 154 people per km² ✓R
d) Ward 7: 0,8 ÷ 2 000,0 × 100% ✓M = 0,04% ✓A
Rounded to one decimal place this is 0,0% ✓R, so the table would show that the area takes up nothing, which is misleading — the value is left out instead ✓O
Modelled on Nov 2024 Paper 2, Question 5.3 — same skills, new scenario.
Question 10
A teacher gave her class the statements in TABLE 1 to revise the concepts of measurement, maps and plans.
TABLE 1: REVISION STATEMENTS
| LETTER | STATEMENT |
|---|---|
| A | A drawing of the inside of a building, seen from above, that shows the rooms, doors and windows |
| B | A scale that stays correct when the map is enlarged or reduced on a photocopier |
| C | The amount of space inside a container, measured in cubic units |
| D | The distance travelled divided by the time taken |
| E | The distance around a circle |
| F | The number of square units that cover a flat surface |
| G | A drawing of the outside of a building as seen from one side |
| H | The time taken multiplied by the average speed |
| I | The total length of the boundary of a flat shape |
| J | A scale such as 1 : 25 000, which has no units |
Pick the statement in TABLE 1 that describes EACH of the concepts below. Give only the letter (A–J) of the statement, for example (f) K.
- aFloor plan (2)
- bBar scale (2)
- cArea (2)
- dAverage speed (2)
- eCircumference (2)
Hint
Area is measured in SQUARE units; a circumference is a length.
Worked answer
a) A ✓✓A — a floor plan is a view from above of the inside; G describes an elevation.
b) B ✓✓A — a bar scale is enlarged or reduced together with the map; a number scale (J) becomes wrong.
c) F ✓✓A — area counts the square units that cover a surface; C describes a volume (capacity).
d) D ✓✓A — speed = distance ÷ time; H describes a distance.
e) E ✓✓A — the circumference is the perimeter of a circle.
Modelled on Nov 2025 Paper 2, Question 1.1 — same skills, new scenario.
Question 11
A bus company gives every passenger an information card. The card for a trip from Durban to Bloemfontein is shown below.
TRIP INFORMATION CARD
| Date | Friday, 12 December 2025 |
| Route | Durban – Bloemfontein |
| Distance | 635 km |
| Maximum number of passengers | 60 |
| Departure time | 07:45 |
| Arrival time | 16:20 |
- aWrite the arrival time (16:20) in words, using the 12-hour format. (2)
- bThe company keeps 16⅔% of the seats for pensioners. Determine the number of seats that are kept for pensioners. (2)
- cWhich ONE of the following methods can be used to calculate the average speed of the bus? - A distance × time - B distance ÷ time - C time ÷ distance (2)
- dTickets for this trip went on sale exactly TWO weeks before the date of the trip. Write down the day of the week on which the tickets went on sale. (2)
Hint
Two weeks are exactly 14 days, so the day of the week stays the same.
Worked answer
a) Twenty past four in the afternoon ✓✓A (accept: 4:20 p.m. written in words)
b) 16⅔% = , so × 60 ✓M = 10 ✓A
c) B ✓✓A — speed = distance ÷ time.
d) Friday ✓✓A (14 days earlier is 28 November 2025; a whole number of weeks does not change the day of the week)
Modelled on Nov 2025 Paper 2, Question 1.2 — same skills, new scenario.
Question 12
Nomsa makes sailboat wall decorations from felt. The template has three triangular parts, as shown in the diagram (not drawn to scale). She decorates each sailboat with rows of coloured beads.
- Part A (main sail): the dimensions are shown on the diagram.
- Part B (front sail): its area is 6 750 mm².
- Part C (hull): its area is TWICE the area of Part A (main sail).
NUMBER OF BEADS PER COLOUR
| COLOUR | Red | Gold | Blue | Green | Silver |
|---|---|---|---|---|---|
| NUMBER | 12 | 9 | 8 | 6 | 7 |
You may use the following formula:
Area of a triangle = ½ × base × height
- aNomsa finished a sailboat at 15:10 after working on it for 2 hours and 35 minutes without a break. Determine the time at which she started. (2)
- bThe beads are sewn on in 4 rows. The first row has 9 beads, and every following row has ONE bead more than the row before it. Determine the total number of beads on one sailboat. (3)
- cCalculate the area of Part A (main sail) in cm². (4)
- dCalculate the total area of the template (all three parts) in mm². NOTE: 1 cm² = 100 mm² (5)
- eOne bead comes loose. Determine, as a percentage rounded to ONE decimal place, the probability that the bead is gold or silver. (4)
This question has a diagram, shown in the app.
Hint
The height is in millimetres but the base is in centimetres — make the units the same before you use the formula.
Worked answer
a) 15:10 − 2 h 35 min ✓M = 12:35 ✓A
b) 9 + 10 + 11 + 12 ✓M ✓M
= 42 beads ✓A
c) Height = 180 mm ÷ 10 = 18 cm ✓C
Area = ½ × 12 cm × 18 cm ✓SF ✓M
= 108 cm² ✓A
d) Part A (main sail) = 108 cm² × 100 ✓C = 10 800 mm² ✓A
Part C (hull) = 2 × 10 800 mm² ✓M = 21 600 mm²
Total = 10 800 + 6 750 + 21 600 ✓M
= 39 150 mm² ✓CA
e) Favourable = 9 + 7 = 16 ✓M
P = ✓M × 100% ✓M
= 38,1% ✓A
Modelled on Nov 2025 Paper 2, Question 3.1 — same skills, new scenario.
Question 13
A youth group makes snowman fridge magnets from craft foam. A magnet consists of a small circle (the head, radius 2,5 cm) on top of a large circle (the body), as shown in the diagram. Each magnet is cut out TWICE, so that the front and the back can be glued together with a magnetic strip between them.
You may use the following formulae (use π = 3,142):
Circumference of a circle = 2 × π × radius
Area of a circle = π × radius²
- aWhat fraction of the radius of the large circle is the radius of the small circle? Give the fraction in its simplest form. (2)
- bCalculate the circumference of the large circle, rounded to the nearest centimetre. (3)
- cThe group buys a piece of craft foam that is 45 cm wide and 1 m long and makes 25 magnets from it. The leader states that MORE than 900 cm² of foam will be left over. (Ignore the small pieces between the circles.) Verify, showing ALL calculations, whether this statement is valid. (9)
This question has a diagram, shown in the app.
Hint
Every magnet needs FOUR circles: two large and two small.
Worked answer
a) ✓M = ✓A
b) Circumference = 2 × 3,142 × 4 cm ✓SF
= 25,136 cm ✓A
≈ 25 cm ✓R
c) Area of the large circle = 3,142 × 4² ✓SF = 50,272 cm² ✓A
Area of the small circle = 3,142 × 2,5² ✓SF = 19,638 cm² ✓A
One magnet (front and back) = 2 × (50,272 + 19,638) ✓M = 139,819 cm²
25 magnets: 139,819 × 25 ✓M = 3 495,48 cm²
Material bought = (1 m = 100 cm) 45 cm × 100 cm ✓C ✓M = 4 500 cm²
Left over = 4 500 − 3 495,48 = 1 004,53 cm²
1 004,53 cm² is more than 900 cm², so the statement is VALID ✓O
Modelled on Nov 2025 Paper 2, Question 3.2 — same skills, new scenario.
Question 14
A team of engineering students bought the solar cells for a solar-powered aircraft on 12 January 2025, and the aircraft started a long-distance demonstration flight on 12 July 2025. It took off at A, spent a night on the ground at C, and landed at E; the map shows the tracked flight. On the last day it took off from C at 05:50 on Sunday 13 July and flew NON-STOP for 7 hours and 45 minutes to E, a distance of 496 km. The whole tracked path from A to E was 1 012 km long, whereas the straight-line distance from A to E is 580 miles.
You may use the following information:
Average speed = distance ÷ time
1 mile = 1,609 km
- aDetermine the number of months between the day on which the solar cells were bought and the day on which the flight started. (2)
- bDetermine the date and the time at which the aircraft landed at E. (3)
- cA town on the map is chosen at random. Determine, as a fraction in simplified form, the probability that the aircraft flew directly over this town (count the towns at the start and at the end of the flight too). (2)
- dCalculate the average speed, in km/h, of the aircraft on the non-stop flight from C to E. (4)
- eThe team leader states that the aircraft flew MORE than 75 km further than the straight-line distance from A to E. Verify, showing ALL calculations, whether this statement is valid. (5)
- fThe country in which the flight took place has 61 million people: 67% of them live in towns and cities, and 42% of THESE people live in the three regions on the map. Calculate the number of people who live in the towns and cities of the three regions. Give your answer to the nearest million. (5)
This question has a diagram, shown in the app.
Hint
The second percentage is taken of the ANSWER to the first percentage, not of the whole population.
Worked answer
a) From 12 January 2025 to 12 July 2025 ✓M = 6 months ✓A
b) 05:50 + 7 h 45 min ✓M = 13:35 ✓A on the same day, 13 July ✓A
c) Towns directly under the path: Sandkraal, Rietpoort, Springvale = 3 of the 9 towns ✓RM
P = = ✓A
d) Time = 7 h 45 min = 7 h + 45 ÷ 60 h ✓M = 7,75 h ✓C
Average speed = 496 km ÷ 7,75 h ✓SF
= 64 km/h ✓A
e) Straight-line distance = 580 miles × 1,609 ✓C ✓M = 933,22 km ✓A
Extra distance = 1 012 km − 933,22 km ✓M = 78,78 km
78,78 km is more than 75 km, so the statement is VALID ✓O
f) 67% of 61 million ✓M = 40,87 million ✓A
42% of 40,87 million ✓M = 17,165 million ✓A
≈ 17 million ✓R
Modelled on Nov 2025 Paper 2, Question 4.2 — same skills, new scenario.
Question 15
Calculate the area of board that is left over after pieces A (bottom), B (side), C (top), D (front trim strip), E (shelf) for THREE shoe racks have been cut. Ignore the width of the saw cuts.
Hint
Remember the 'number needed' column: two sides and three shelves per rack — and then everything three times.
Worked answer
a) A: 1 × 86 × 32 = 2 752 cm²
B: 2 × 98 × 32 = 6 272 cm²
C: 1 × 90 × 32 = 2 880 cm²
D: 1 × 90 × 4 = 360 cm²
E: 3 × 86 × 30 = 7 740 cm² ✓M (areas of the pieces) ✓A
One shoe rack = 2 752 + 6 272 + 2 880 + 360 + 7 740 = 20 004 cm² ✓A
Three shoe racks = 3 × 20 004 ✓M = 60 012 cm²
Area bought = 2 × 275 × 183 ✓M = 100 650 cm²
Area left = 100 650 − 60 012 = 40 638 cm² ✓CA
Modelled on Nov 2025 Paper 2, Question 5.2 — same skills, new scenario.
Question 16
The carpenter states that it takes LESS than 6 months to collect ONE ton of offcuts.
Verify, showing ALL calculations, whether this statement is valid.
Hint
Convert the volume to cm³ first, because the density is given in grams per cm³.
Worked answer
a) Volume per month = 0,35 m³ × 1 000 000 = 350 000 cm³ ✓C
Mass per month = density × volume = 0,52 g/cm³ × 350 000 cm³ ✓SF
= 182 000 g ✓A
= 182 000 g ÷ 1 000 000 = 0,182 ton ✓C
Number of months for 1 ton = 1 ÷ 0,182 ✓M = 5,49 months
5,49 months is LESS than 6 months, so the statement is VALID ✓O
Modelled on Nov 2025 Paper 2, Question 5.3 — same skills, new scenario.